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140013043303011 = 31812549101157673
BaseRepresentation
bin11111110101011101010011…
…101101011100001001100011
3200100202010010201111222121220
4133311131103231130021203
5121322433203041144021
61213441034254150123
741330415510366414
oct3765352355341143
9610663121458556
10140013043303011
114068121a8a290a
1213853570ab2343
136018233a64488
14268094b6c980b
15112c0d9643cc6
hex7f5753b5c263

140013043303011 has 16 divisors (see below), whose sum is σ = 187789106013600. Its totient is φ = 92789909372160.

The previous prime is 140013043302983. The next prime is 140013043303037. The reversal of 140013043303011 is 110303340310041.

It is not a de Polignac number, because 140013043303011 - 210 = 140013043301987 is a prime.

It is a super-2 number, since 2×1400130433030112 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (140013043303061) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49194730 + ... + 51962943.

It is an arithmetic number, because the mean of its divisors is an integer number (11736819125850).

Almost surely, 2140013043303011 is an apocalyptic number.

140013043303011 is a deficient number, since it is larger than the sum of its proper divisors (47776062710589).

140013043303011 is a wasteful number, since it uses less digits than its factorization.

140013043303011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 101160406.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 140013043303011 its reverse (110303340310041), we get a palindrome (250316383613052).

The spelling of 140013043303011 in words is "one hundred forty trillion, thirteen billion, forty-three million, three hundred three thousand, eleven".

Divisors: 1 3 181 543 2549 7647 461369 1384107 101157673 303473019 18309538813 54928616439 257850908477 773552725431 46671014434337 140013043303011