140014053115 has 4 divisors (see below), whose sum is σ = 168016863744. Its totient is φ = 112011242488.

The previous prime is 140014053103. The next prime is 140014053133. The reversal of 140014053115 is 511350410041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511350410041 = 173 ⋅2955782717.

It is a cyclic number.

It is not a de Polignac number, because 140014053115 - 2⁹ = 140014052603 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 140014053115.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14001405307 + ... + 14001405316.

It is an arithmetic number, because the mean of its divisors is an integer number (42004215936).

Almost surely, 2^140014053115 is an apocalyptic number.

140014053115 is a deficient number, since it is larger than the sum of its proper divisors (28002810629).

140014053115 is an equidigital number, since it uses as much as digits as its factorization.

140014053115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28002810628.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 140014053115 its reverse (511350410041), we get a palindrome (651364463156).

The spelling of 140014053115 in words is "one hundred forty billion, fourteen million, fifty-three thousand, one hundred fifteen".