1400142400113 has 8 divisors (see below), whose sum is σ = 1867323146976. Its totient is φ = 933194960000.

The previous prime is 1400142400109. The next prime is 1400142400171. The reversal of 1400142400113 is 3110042410041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1400142400113 - 2² = 1400142400109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1400142400113.

It is not an unprimeable number, because it can be changed into a prime (1400142400183) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 58312683 + ... + 58336688.

It is an arithmetic number, because the mean of its divisors is an integer number (233415393372).

Almost surely, 2^{1400142400113} is an apocalyptic number.

It is an amenable number.

1400142400113 is a deficient number, since it is larger than the sum of its proper divisors (467180746863).

1400142400113 is a wasteful number, since it uses less digits than its factorization.

1400142400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 116653375.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 1400142400113 its reverse (3110042410041), we get a palindrome (4510184810154).

The spelling of 1400142400113 in words is "one trillion, four hundred billion, one hundred forty-two million, four hundred thousand, one hundred thirteen".