1400153442133 has 4 divisors (see below), whose sum is σ = 1448434595340. Its totient is φ = 1351872288928.

The previous prime is 1400153442109. The next prime is 1400153442173. The reversal of 1400153442133 is 3312443510041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 796390253649 + 603763188484 = 892407^2 + 777022^2 .

It is a cyclic number.

It is not a de Polignac number, because 1400153442133 - 2²⁵ = 1400119887701 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1400153442095 and 1400153442104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1400153442173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24140576560 + ... + 24140576617.

It is an arithmetic number, because the mean of its divisors is an integer number (362108648835).

Almost surely, 2^{1400153442133} is an apocalyptic number.

It is an amenable number.

1400153442133 is a deficient number, since it is larger than the sum of its proper divisors (48281153207).

1400153442133 is an equidigital number, since it uses as much as digits as its factorization.

1400153442133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48281153206.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 1400153442133 its reverse (3312443510041), we get a palindrome (4712596952174).

The spelling of 1400153442133 in words is "one trillion, four hundred billion, one hundred fifty-three million, four hundred forty-two thousand, one hundred thirty-three".