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14002124433 = 3112914631269
BaseRepresentation
bin11010000101001011…
…10111011010010001
31100010211110121202020
431002211313122101
5212134020440213
610233230042053
71003662044133
oct150245673221
940124417666
1014002124433
115a3591a370
122869349329
131421ba3b3b
1496b8ab053
1556e402923
hex342977691

14002124433 has 16 divisors (see below), whose sum is σ = 21069028800. Its totient is φ = 8193510080.

The previous prime is 14002124429. The next prime is 14002124441. The reversal of 14002124433 is 33442120041.

14002124433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 14002124433 - 22 = 14002124429 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14002124453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7314678 + ... + 7316591.

It is an arithmetic number, because the mean of its divisors is an integer number (1316814300).

Almost surely, 214002124433 is an apocalyptic number.

It is an amenable number.

14002124433 is a deficient number, since it is larger than the sum of its proper divisors (7066904367).

14002124433 is a wasteful number, since it uses less digits than its factorization.

14002124433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14631312.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 14002124433 its reverse (33442120041), we get a palindrome (47444244474).

The spelling of 14002124433 in words is "fourteen billion, two million, one hundred twenty-four thousand, four hundred thirty-three".

Divisors: 1 3 11 29 33 87 319 957 14631269 43893807 160943959 424306801 482831877 1272920403 4667374811 14002124433