140022121124401 has 4 divisors (see below), whose sum is σ = 143437294810404. Its totient is φ = 136606947438400.

The previous prime is 140022121124341. The next prime is 140022121124429. The reversal of 140022121124401 is 104421121220041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 47411831640625 + 92610289483776 = 6885625^2 + 9623424^2 .

It is a cyclic number.

It is not a de Polignac number, because 140022121124401 - 2³³ = 140013531189809 is a prime.

It is a super-3 number, since 3×140022121124401³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140022121128401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1707586842940 + ... + 1707586843021.

It is an arithmetic number, because the mean of its divisors is an integer number (35859323702601).

Almost surely, 2^{140022121124401} is an apocalyptic number.

It is an amenable number.

140022121124401 is a deficient number, since it is larger than the sum of its proper divisors (3415173686003).

140022121124401 is an equidigital number, since it uses as much as digits as its factorization.

140022121124401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3415173686002.

The product of its (nonzero) digits is 1024, while the sum is 25.

Adding to 140022121124401 its reverse (104421121220041), we get a palindrome (244443242344442).

The spelling of 140022121124401 in words is "one hundred forty trillion, twenty-two billion, one hundred twenty-one million, one hundred twenty-four thousand, four hundred one".