14002232021301 has 8 divisors (see below), whose sum is σ = 18747758355840. Its totient is φ = 9295763517152.

The previous prime is 14002232021299. The next prime is 14002232021359. The reversal of 14002232021301 is 10312023220041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14002232021301 - 2¹ = 14002232021299 is a prime.

It is a super-3 number, since 3×14002232021301³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14002232021381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9764456760 + ... + 9764458193.

It is an arithmetic number, because the mean of its divisors is an integer number (2343469794480).

Almost surely, 2^{14002232021301} is an apocalyptic number.

It is an amenable number.

14002232021301 is a deficient number, since it is larger than the sum of its proper divisors (4745526334539).

14002232021301 is a wasteful number, since it uses less digits than its factorization.

14002232021301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19528915195.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14002232021301 its reverse (10312023220041), we get a palindrome (24314255241342).

The spelling of 14002232021301 in words is "fourteen trillion, two billion, two hundred thirty-two million, twenty-one thousand, three hundred one".