Base | Representation |
---|---|
bin | 11111110101101101001000… |
… | …011100010100010111111011 |
3 | 200100210201222211202122201220 |
4 | 133311231020130110113323 |
5 | 121323223002214301043 |
6 | 1213452524250443123 |
7 | 41331556533153351 |
oct | 3765551034242773 |
9 | 610721884678656 |
10 | 140030034134523 |
11 | 4068844976a025 |
12 | 138569131334a3 |
13 | 6019a10b97630 |
14 | 26816c009d7d1 |
15 | 112c781109483 |
hex | 7f5b487145fb |
140030034134523 has 32 divisors (see below), whose sum is σ = 201727490587392. Its totient is φ = 85890029097600.
The previous prime is 140030034134491. The next prime is 140030034134533. The reversal of 140030034134523 is 325431430030041.
It is not a de Polignac number, because 140030034134523 - 25 = 140030034134491 is a prime.
It is not an unprimeable number, because it can be changed into a prime (140030034134533) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1106972308 + ... + 1107098798.
It is an arithmetic number, because the mean of its divisors is an integer number (6303984080856).
Almost surely, 2140030034134523 is an apocalyptic number.
140030034134523 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
140030034134523 is a deficient number, since it is larger than the sum of its proper divisors (61697456452869).
140030034134523 is a wasteful number, since it uses less digits than its factorization.
140030034134523 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 219275.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 140030034134523 its reverse (325431430030041), we get a palindrome (465461464164564).
The spelling of 140030034134523 in words is "one hundred forty trillion, thirty billion, thirty-four million, one hundred thirty-four thousand, five hundred twenty-three".
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