140031003144042 has 12 divisors (see below), whose sum is σ = 303400506812130. Its totient is φ = 46677001048008.

The previous prime is 140031003144001. The next prime is 140031003144061. The reversal of 140031003144042 is 240441300130041.

140031003144042 is a `hidden beast` number, since 140 + 0 + 3 + 10 + 0 + 31 + 440 + 42 = 666.

It can be written as a sum of positive squares in only one way, i.e., 102869677415961 + 37161325728081 = 10142469^2 + 6096009^2 .

It is a junction number, because it is equal to n+sod(n) for n = 140031003143997 and 140031003144015.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3889750087317 + ... + 3889750087352.

Almost surely, 2^{140031003144042} is an apocalyptic number.

140031003144042 is an abundant number, since it is smaller than the sum of its proper divisors (163369503668088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140031003144042 is a wasteful number, since it uses less digits than its factorization.

140031003144042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7779500174677 (or 7779500174674 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 140031003144042 its reverse (240441300130041), we get a palindrome (380472303274083).

The spelling of 140031003144042 in words is "one hundred forty trillion, thirty-one billion, three million, one hundred forty-four thousand, forty-two".