Base | Representation |
---|---|
bin | 1100101111000101101100… |
… | …1110110101100111011011 |
3 | 1211120200111210021122211021 |
4 | 3023301123032311213123 |
5 | 3313411344221014433 |
6 | 45440540225143311 |
7 | 2643456316050646 |
oct | 313613316654733 |
9 | 54520453248737 |
10 | 14003124001243 |
11 | 450976748aaa3 |
12 | 16a1a95a8ab37 |
13 | 7a76482336b0 |
14 | 365a7d312a5d |
15 | 1943c02d822d |
hex | cbc5b3b59db |
14003124001243 has 4 divisors (see below), whose sum is σ = 15080287385968. Its totient is φ = 12925960616520.
The previous prime is 14003124001193. The next prime is 14003124001289. The reversal of 14003124001243 is 34210042130041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14003124001243 - 217 = 14003123870171 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14003124041243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 538581692343 + ... + 538581692368.
It is an arithmetic number, because the mean of its divisors is an integer number (3770071846492).
Almost surely, 214003124001243 is an apocalyptic number.
14003124001243 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
14003124001243 is a deficient number, since it is larger than the sum of its proper divisors (1077163384725).
14003124001243 is a wasteful number, since it uses less digits than its factorization.
14003124001243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1077163384724.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14003124001243 its reverse (34210042130041), we get a palindrome (48213166131284).
The spelling of 14003124001243 in words is "fourteen trillion, three billion, one hundred twenty-four million, one thousand, two hundred forty-three".
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