140031421104343 has 4 divisors (see below), whose sum is σ = 140069986632928. Its totient is φ = 139992855575760.

The previous prime is 140031421104313. The next prime is 140031421104349. The reversal of 140031421104343 is 343401124130041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140031421104343 - 2⁴¹ = 137832397848791 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140031421104349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19282758846 + ... + 19282766107.

It is an arithmetic number, because the mean of its divisors is an integer number (35017496658232).

Almost surely, 2^{140031421104343} is an apocalyptic number.

140031421104343 is a deficient number, since it is larger than the sum of its proper divisors (38565528585).

140031421104343 is an equidigital number, since it uses as much as digits as its factorization.

140031421104343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38565528584.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 140031421104343 its reverse (343401124130041), we get a palindrome (483432545234384).

The spelling of 140031421104343 in words is "one hundred forty trillion, thirty-one billion, four hundred twenty-one million, one hundred four thousand, three hundred forty-three".