140032040115 has 32 divisors (see below), whose sum is σ = 248426456832. Its totient is φ = 66781296000.

The previous prime is 140032040107. The next prime is 140032040117. The reversal of 140032040115 is 511040230041.

140032040115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 140032040115 - 2³ = 140032040107 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140032040091 and 140032040100.

It is not an unprimeable number, because it can be changed into a prime (140032040117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6946321 + ... + 6966450.

It is an arithmetic number, because the mean of its divisors is an integer number (7763326776).

Almost surely, 2^140032040115 is an apocalyptic number.

140032040115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

140032040115 is a deficient number, since it is larger than the sum of its proper divisors (108394416717).

140032040115 is a wasteful number, since it uses less digits than its factorization.

140032040115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13912851.

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 140032040115 its reverse (511040230041), we get a palindrome (651072270156).

The spelling of 140032040115 in words is "one hundred forty billion, thirty-two million, forty thousand, one hundred fifteen".