140032401111221 has 8 divisors (see below), whose sum is σ = 140383617012888. Its totient is φ = 139681195200000.

The previous prime is 140032401111217. The next prime is 140032401111269. The reversal of 140032401111221 is 122111104230041.

It can be written as a sum of positive squares in 4 ways, for example, as 115509057180196 + 24523343931025 = 10747514^2 + 4952105^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140032401111221 - 2² = 140032401111217 is a prime.

It is a super-2 number, since 2×140032401111221² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140032401111521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25977371 + ... + 30901271.

It is an arithmetic number, because the mean of its divisors is an integer number (17547952126611).

Almost surely, 2^{140032401111221} is an apocalyptic number.

It is an amenable number.

140032401111221 is a deficient number, since it is larger than the sum of its proper divisors (351215901667).

140032401111221 is an equidigital number, since it uses as much as digits as its factorization.

140032401111221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4995223.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 140032401111221 its reverse (122111104230041), we get a palindrome (262143505341262).

The spelling of 140032401111221 in words is "one hundred forty trillion, thirty-two billion, four hundred one million, one hundred eleven thousand, two hundred twenty-one".