140033113031001 has 4 divisors (see below), whose sum is σ = 186710817374672. Its totient is φ = 93355408687332.

The previous prime is 140033113030981. The next prime is 140033113031047. The reversal of 140033113031001 is 100130311330041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 140033113031001 - 2¹¹ = 140033113028953 is a prime.

It is a super-3 number, since 3×140033113031001³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (140033113031401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23338852171831 + ... + 23338852171836.

It is an arithmetic number, because the mean of its divisors is an integer number (46677704343668).

Almost surely, 2^{140033113031001} is an apocalyptic number.

It is an amenable number.

140033113031001 is a deficient number, since it is larger than the sum of its proper divisors (46677704343671).

140033113031001 is an equidigital number, since it uses as much as digits as its factorization.

140033113031001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46677704343670.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 140033113031001 its reverse (100130311330041), we get a palindrome (240163424361042).

The spelling of 140033113031001 in words is "one hundred forty trillion, thirty-three billion, one hundred thirteen million, thirty-one thousand, one".