140033113031000 has 256 divisors, whose sum is σ = 400155102547200. Its totient is φ = 44772590592000.

The previous prime is 140033113030981. The next prime is 140033113031047. The reversal of 140033113031000 is 130311330041.

It is a super-3 number, since 3×140033113031000³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 7573070 + ... + 18368930.

It is an arithmetic number, because the mean of its divisors is an integer number (1563105869325).

Almost surely, 2^{140033113031000} is an apocalyptic number.

140033113031000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 140033113031000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (200077551273600).

140033113031000 is an abundant number, since it is smaller than the sum of its proper divisors (260121989516200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140033113031000 is a wasteful number, since it uses less digits than its factorization.

140033113031000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10796015 (or 10796001 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 140033113031000 its reverse (130311330041), we get a palindrome (140163424361041).

The spelling of 140033113031000 in words is "one hundred forty trillion, thirty-three billion, one hundred thirteen million, thirty-one thousand".