140033114120401 has 4 divisors (see below), whose sum is σ = 140033183560704. Its totient is φ = 140033044680100.

The previous prime is 140033114120363. The next prime is 140033114120447. The reversal of 140033114120401 is 104021411330041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140033114120401 - 2¹⁹ = 140033113596113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140033114130401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31601905 + ... + 35759566.

It is an arithmetic number, because the mean of its divisors is an integer number (35008295890176).

Almost surely, 2^{140033114120401} is an apocalyptic number.

It is an amenable number.

140033114120401 is a deficient number, since it is larger than the sum of its proper divisors (69440303).

140033114120401 is an equidigital number, since it uses as much as digits as its factorization.

140033114120401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 69440302.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 140033114120401 its reverse (104021411330041), we get a palindrome (244054525450442).

The spelling of 140033114120401 in words is "one hundred forty trillion, thirty-three billion, one hundred fourteen million, one hundred twenty thousand, four hundred one".