140033130321211 has 4 divisors (see below), whose sum is σ = 140033154113800. Its totient is φ = 140033106528624.

The previous prime is 140033130321187. The next prime is 140033130321223. The reversal of 140033130321211 is 112123031330041.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 140033130321211 - 2⁵ = 140033130321179 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140033130351211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4117975 + ... + 17234383.

It is an arithmetic number, because the mean of its divisors is an integer number (35008288528450).

Almost surely, 2^{140033130321211} is an apocalyptic number.

140033130321211 is a deficient number, since it is larger than the sum of its proper divisors (23792589).

140033130321211 is a wasteful number, since it uses less digits than its factorization.

140033130321211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23792588.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 140033130321211 its reverse (112123031330041), we get a palindrome (252156161651252).

The spelling of 140033130321211 in words is "one hundred forty trillion, thirty-three billion, one hundred thirty million, three hundred twenty-one thousand, two hundred eleven".