Base | Representation |
---|---|
bin | 1000001001101010101… |
… | …1010101000111101001 |
3 | 111101110012200102200121 |
4 | 2002122223111013221 |
5 | 4243242201102213 |
6 | 144155234403241 |
7 | 13055113250452 |
oct | 2023253250751 |
9 | 441405612617 |
10 | 140034003433 |
11 | 5442a5a9455 |
12 | 23181130521 |
13 | 1028893927c |
14 | 6ac5d60129 |
15 | 3998bdb88d |
hex | 209aad51e9 |
140034003433 has 16 divisors (see below), whose sum is σ = 151323800320. Its totient is φ = 129156276816.
The previous prime is 140034003379. The next prime is 140034003443. The reversal of 140034003433 is 334300430041.
It is a cyclic number.
It is not a de Polignac number, because 140034003433 - 29 = 140034002921 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 140034003398 and 140034003407.
It is not an unprimeable number, because it can be changed into a prime (140034003443) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28335 + ... + 529972.
It is an arithmetic number, because the mean of its divisors is an integer number (9457737520).
Almost surely, 2140034003433 is an apocalyptic number.
It is an amenable number.
140034003433 is a deficient number, since it is larger than the sum of its proper divisors (11289796887).
140034003433 is a wasteful number, since it uses less digits than its factorization.
140034003433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 558676.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 140034003433 its reverse (334300430041), we get a palindrome (474334433474).
The spelling of 140034003433 in words is "one hundred forty billion, thirty-four million, three thousand, four hundred thirty-three".
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