Base | Representation |
---|---|
bin | 10100011000001010110… |
… | …101000101001001001011 |
3 | 11221212112011200200022120 |
4 | 110120022311011021023 |
5 | 140420344300302410 |
6 | 2551150252022323 |
7 | 203112520215036 |
oct | 24301265051113 |
9 | 4855464620276 |
10 | 1400341025355 |
11 | 49a977002728 |
12 | 1a748b4619a3 |
13 | a208946a11c |
14 | 4bac3a1c01d |
15 | 2665d074570 |
hex | 1460ad4524b |
1400341025355 has 64 divisors (see below), whose sum is σ = 2308551598080. Its totient is φ = 724396492800.
The previous prime is 1400341025341. The next prime is 1400341025383. The reversal of 1400341025355 is 5535201430041.
It is not a de Polignac number, because 1400341025355 - 221 = 1400338928203 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 371539911 + ... + 371543679.
It is an arithmetic number, because the mean of its divisors is an integer number (36071118720).
Almost surely, 21400341025355 is an apocalyptic number.
1400341025355 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1400341025355 is a deficient number, since it is larger than the sum of its proper divisors (908210572725).
1400341025355 is a wasteful number, since it uses less digits than its factorization.
1400341025355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7172.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 1400341025355 its reverse (5535201430041), we get a palindrome (6935542455396).
The spelling of 1400341025355 in words is "one trillion, four hundred billion, three hundred forty-one million, twenty-five thousand, three hundred fifty-five".
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