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140041314311 = 612295759251
BaseRepresentation
bin1000001001101100011…
…1001110000000000111
3111101110201102212022212
42002123013032000013
54243301034024221
6144200055214035
713055232350123
oct2023307160007
9441421385285
10140041314311
11544337421a8
122318367731b
131028a2c8b32
146ac6d04583
153999682b5b
hex209b1ce007

140041314311 has 4 divisors (see below), whose sum is σ = 142337073624. Its totient is φ = 137745555000.

The previous prime is 140041314299. The next prime is 140041314313. The reversal of 140041314311 is 113413140041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140041314311 - 214 = 140041297927 is a prime.

It is a super-2 number, since 2×1400413143112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140041314313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1147879565 + ... + 1147879686.

It is an arithmetic number, because the mean of its divisors is an integer number (35584268406).

Almost surely, 2140041314311 is an apocalyptic number.

140041314311 is a deficient number, since it is larger than the sum of its proper divisors (2295759313).

140041314311 is an equidigital number, since it uses as much as digits as its factorization.

140041314311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2295759312.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 140041314311 its reverse (113413140041), we get a palindrome (253454454352).

The spelling of 140041314311 in words is "one hundred forty billion, forty-one million, three hundred fourteen thousand, three hundred eleven".

Divisors: 1 61 2295759251 140041314311