Base | Representation |
---|---|
bin | 11010000101011011… |
… | …00100010011000111 |
3 | 1100010222021012010012 |
4 | 31002231210103013 |
5 | 212140030041203 |
6 | 10233341220435 |
7 | 1004015153063 |
oct | 150255442307 |
9 | 40128235105 |
10 | 14004143303 |
11 | 5a36a79157 |
12 | 2869b6171b |
13 | 142242ca37 |
14 | 96bc74aa3 |
15 | 56e6a0bd8 |
hex | 342b644c7 |
14004143303 has 4 divisors (see below), whose sum is σ = 14007350088. Its totient is φ = 14000936520.
The previous prime is 14004143281. The next prime is 14004143333. The reversal of 14004143303 is 30334140041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14004143303 - 226 = 13937034439 is a prime.
It is a super-2 number, since 2×140041433032 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14004143333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1596833 + ... + 1605578.
It is an arithmetic number, because the mean of its divisors is an integer number (3501837522).
Almost surely, 214004143303 is an apocalyptic number.
14004143303 is a deficient number, since it is larger than the sum of its proper divisors (3206785).
14004143303 is an equidigital number, since it uses as much as digits as its factorization.
14004143303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3206784.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 14004143303 its reverse (30334140041), we get a palindrome (44338283344).
The spelling of 14004143303 in words is "fourteen billion, four million, one hundred forty-three thousand, three hundred three".
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