1400422150051 has 4 divisors (see below), whose sum is σ = 1400425536472. Its totient is φ = 1400418763632.

The previous prime is 1400422150021. The next prime is 1400422150067. The reversal of 1400422150051 is 1500512240041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1400422150051 is a prime.

It is a super-2 number, since 2×1400422150051² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1400422149998 and 1400422150025.

It is not an unprimeable number, because it can be changed into a prime (1400422150021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 969906 + ... + 1934311.

It is an arithmetic number, because the mean of its divisors is an integer number (350106384118).

Almost surely, 2^{1400422150051} is an apocalyptic number.

1400422150051 is a deficient number, since it is larger than the sum of its proper divisors (3386421).

1400422150051 is an equidigital number, since it uses as much as digits as its factorization.

1400422150051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3386420.

The product of its (nonzero) digits is 1600, while the sum is 25.

Adding to 1400422150051 its reverse (1500512240041), we get a palindrome (2900934390092).

The spelling of 1400422150051 in words is "one trillion, four hundred billion, four hundred twenty-two million, one hundred fifty thousand, fifty-one".