1400433101433 has 12 divisors (see below), whose sum is σ = 2072185565268. Its totient is φ = 910850797440.

The previous prime is 1400433101413. The next prime is 1400433101437. The reversal of 1400433101433 is 3341013340041.

It can be written as a sum of positive squares in 2 ways, for example, as 325006028649 + 1075427072784 = 570093^2 + 1037028^2 .

It is not a de Polignac number, because 1400433101433 - 2⁹ = 1400433100921 is a prime.

It is a super-2 number, since 2×1400433101433² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1400433101397 and 1400433101406.

It is not an unprimeable number, because it can be changed into a prime (1400433101437) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1897605460 + ... + 1897606197.

It is an arithmetic number, because the mean of its divisors is an integer number (172682130439).

Almost surely, 2^{1400433101433} is an apocalyptic number.

It is an amenable number.

1400433101433 is a deficient number, since it is larger than the sum of its proper divisors (671752463835).

1400433101433 is a wasteful number, since it uses less digits than its factorization.

1400433101433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3795211704 (or 3795211701 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 1400433101433 its reverse (3341013340041), we get a palindrome (4741446441474).

The spelling of 1400433101433 in words is "one trillion, four hundred billion, four hundred thirty-three million, one hundred one thousand, four hundred thirty-three".