1400433101413 has 2 divisors, whose sum is σ = 1400433101414. Its totient is φ = 1400433101412.

The previous prime is 1400433101411. The next prime is 1400433101437. The reversal of 1400433101413 is 3141013340041.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 808213586049 + 592219515364 = 899007^2 + 769558^2 .

It is a cyclic number.

It is not a de Polignac number, because 1400433101413 - 2¹ = 1400433101411 is a prime.

It is a super-2 number, since 2×1400433101413² (a number of 25 digits) contains 22 as substring.

Together with 1400433101411, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1400433101411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700216550706 + 700216550707.

It is an arithmetic number, because the mean of its divisors is an integer number (700216550707).

Almost surely, 2^{1400433101413} is an apocalyptic number.

It is an amenable number.

1400433101413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400433101413 is an equidigital number, since it uses as much as digits as its factorization.

1400433101413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1400433101413 its reverse (3141013340041), we get a palindrome (4541446441454).

The spelling of 1400433101413 in words is "one trillion, four hundred billion, four hundred thirty-three million, one hundred one thousand, four hundred thirteen".