Base | Representation |
---|---|
bin | 10100011000010000110… |
… | …000001111101101010011 |
3 | 11221212210002201111210021 |
4 | 110120100300033231103 |
5 | 140421100221434303 |
6 | 2551204202244311 |
7 | 203115135112615 |
oct | 24302060175523 |
9 | 4855702644707 |
10 | 1400440421203 |
11 | 49aa1812125a |
12 | 1a74b87b6697 |
13 | a20a3c2b935 |
14 | 4bad2cd2db5 |
15 | 26666b59ebd |
hex | 14610c0fb53 |
1400440421203 has 8 divisors (see below), whose sum is σ = 1448747694000. Its totient is φ = 1352134230048.
The previous prime is 1400440421189. The next prime is 1400440421209. The reversal of 1400440421203 is 3021240440041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1400440421203 - 213 = 1400440413011 is a prime.
It is a super-2 number, since 2×14004404212032 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1400440421209) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3058473 + ... + 3486421.
It is an arithmetic number, because the mean of its divisors is an integer number (181093461750).
Almost surely, 21400440421203 is an apocalyptic number.
1400440421203 is a deficient number, since it is larger than the sum of its proper divisors (48307272797).
1400440421203 is a wasteful number, since it uses less digits than its factorization.
1400440421203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 540821.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 1400440421203 its reverse (3021240440041), we get a palindrome (4421680861244).
The spelling of 1400440421203 in words is "one trillion, four hundred billion, four hundred forty million, four hundred twenty-one thousand, two hundred three".
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