1400444344421 has 4 divisors (see below), whose sum is σ = 1400528893152. Its totient is φ = 1400359795692.

The previous prime is 1400444344393. The next prime is 1400444344423. The reversal of 1400444344421 is 1244434440041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1400444344421 - 2³⁸ = 1125566437477 is a prime.

It is a super-2 number, since 2×1400444344421² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1400444344423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42249515 + ... + 42282648.

It is an arithmetic number, because the mean of its divisors is an integer number (350132223288).

Almost surely, 2^{1400444344421} is an apocalyptic number.

It is an amenable number.

1400444344421 is a deficient number, since it is larger than the sum of its proper divisors (84548731).

1400444344421 is an equidigital number, since it uses as much as digits as its factorization.

1400444344421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84548730.

The product of its (nonzero) digits is 98304, while the sum is 35.

Adding to 1400444344421 its reverse (1244434440041), we get a palindrome (2644878784462).

The spelling of 1400444344421 in words is "one trillion, four hundred billion, four hundred forty-four million, three hundred forty-four thousand, four hundred twenty-one".