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14005045555 = 52801009111
BaseRepresentation
bin11010000101100010…
…00000100100110011
31100011000222000202221
431002301000210303
5212140242424210
610233412421511
71004025631414
oct150261004463
940130860687
1014005045555
115a37535016
12286a317897
131422687607
1496c02b80b
1556e7cd1da
hex342c40933

14005045555 has 4 divisors (see below), whose sum is σ = 16806054672. Its totient is φ = 11204036440.

The previous prime is 14005045541. The next prime is 14005045601. The reversal of 14005045555 is 55554050041.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-14005045555 is a prime.

It is a super-2 number, since 2×140050455552 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14005045555.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1400504551 + ... + 1400504560.

It is an arithmetic number, because the mean of its divisors is an integer number (4201513668).

Almost surely, 214005045555 is an apocalyptic number.

14005045555 is a deficient number, since it is larger than the sum of its proper divisors (2801009117).

14005045555 is an equidigital number, since it uses as much as digits as its factorization.

14005045555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2801009116.

The product of its (nonzero) digits is 50000, while the sum is 34.

Adding to 14005045555 its reverse (55554050041), we get a palindrome (69559095596).

The spelling of 14005045555 in words is "fourteen billion, five million, forty-five thousand, five hundred fifty-five".

Divisors: 1 5 2801009111 14005045555