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14005135403 = 75857341597
BaseRepresentation
bin11010000101100010…
…10110100000101011
31100011001010121000122
431002301112200223
5212140303313103
610233414353455
71004026454360
oct150261264053
940131117018
1014005135403
115a37596576
12286a35b88b
1314226b948c
1496c052467
1556e7e9b38
hex342c5682b

14005135403 has 8 divisors (see below), whose sum is σ = 16008648672. Its totient is φ = 12002317056.

The previous prime is 14005135373. The next prime is 14005135411. The reversal of 14005135403 is 30453150041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14005135403 - 212 = 14005131307 is a prime.

It is a super-2 number, since 2×140051354032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14005135423) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 129800 + ... + 211797.

It is an arithmetic number, because the mean of its divisors is an integer number (2001081084).

Almost surely, 214005135403 is an apocalyptic number.

14005135403 is a deficient number, since it is larger than the sum of its proper divisors (2003513269).

14005135403 is an equidigital number, since it uses as much as digits as its factorization.

14005135403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 347461.

The product of its (nonzero) digits is 3600, while the sum is 26.

Adding to 14005135403 its reverse (30453150041), we get a palindrome (44458285444).

The spelling of 14005135403 in words is "fourteen billion, five million, one hundred thirty-five thousand, four hundred three".

Divisors: 1 7 5857 40999 341597 2391179 2000733629 14005135403