Base | Representation |
---|---|
bin | 11010000101100010… |
… | …10101100000101011 |
3 | 1100011001010101101221 |
4 | 31002301111200223 |
5 | 212140303200212 |
6 | 10233414322511 |
7 | 1004026436416 |
oct | 150261254053 |
9 | 40131111357 |
10 | 14005131307 |
11 | 5a37593492 |
12 | 286a359437 |
13 | 14226b765b |
14 | 96c050b7d |
15 | 56e7e8807 |
hex | 342c5582b |
14005131307 has 2 divisors, whose sum is σ = 14005131308. Its totient is φ = 14005131306.
The previous prime is 14005131293. The next prime is 14005131311. The reversal of 14005131307 is 70313150041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14005131307 - 227 = 13870913579 is a prime.
It is a super-2 number, since 2×140051313072 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14005131317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7002565653 + 7002565654.
It is an arithmetic number, because the mean of its divisors is an integer number (7002565654).
Almost surely, 214005131307 is an apocalyptic number.
14005131307 is a deficient number, since it is larger than the sum of its proper divisors (1).
14005131307 is an equidigital number, since it uses as much as digits as its factorization.
14005131307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1260, while the sum is 25.
Adding to 14005131307 its reverse (70313150041), we get a palindrome (84318281348).
The spelling of 14005131307 in words is "fourteen billion, five million, one hundred thirty-one thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.124 sec. • engine limits •