Base | Representation |
---|---|
bin | 11010000101100100… |
… | …00001100110100111 |
3 | 1100011001110120010222 |
4 | 31002302001212213 |
5 | 212140324440121 |
6 | 10233422234555 |
7 | 1004031121103 |
oct | 150262014647 |
9 | 40131416128 |
10 | 14005311911 |
11 | 5a376a7148 |
12 | 286a425a5b |
13 | 142274b916 |
14 | 96c09a903 |
15 | 56e8320ab |
hex | 342c819a7 |
14005311911 has 4 divisors (see below), whose sum is σ = 14005587792. Its totient is φ = 14005036032.
The previous prime is 14005311907. The next prime is 14005311959. The reversal of 14005311911 is 11911350041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14005311911 - 22 = 14005311907 is a prime.
It is a super-2 number, since 2×140053119112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14005311311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37331 + ... + 171476.
It is an arithmetic number, because the mean of its divisors is an integer number (3501396948).
Almost surely, 214005311911 is an apocalyptic number.
14005311911 is a deficient number, since it is larger than the sum of its proper divisors (275881).
14005311911 is an equidigital number, since it uses as much as digits as its factorization.
14005311911 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 275880.
The product of its (nonzero) digits is 540, while the sum is 26.
Adding to 14005311911 its reverse (11911350041), we get a palindrome (25916661952).
The spelling of 14005311911 in words is "fourteen billion, five million, three hundred eleven thousand, nine hundred eleven".
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