14010122333131 has 4 divisors (see below), whose sum is σ = 14462061763264. Its totient is φ = 13558182903000.

The previous prime is 14010122333117. The next prime is 14010122333143. The reversal of 14010122333131 is 13133322101041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14010122333131 - 2¹⁹ = 14010121808843 is a prime.

It is a super-2 number, since 2×14010122333131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14010122333096 and 14010122333105.

It is not an unprimeable number, because it can be changed into a prime (14010122333161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225969715020 + ... + 225969715081.

It is an arithmetic number, because the mean of its divisors is an integer number (3615515440816).

Almost surely, 2^{14010122333131} is an apocalyptic number.

14010122333131 is a deficient number, since it is larger than the sum of its proper divisors (451939430133).

14010122333131 is an equidigital number, since it uses as much as digits as its factorization.

14010122333131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 451939430132.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 14010122333131 its reverse (13133322101041), we get a palindrome (27143444434172).

The spelling of 14010122333131 in words is "fourteen trillion, ten billion, one hundred twenty-two million, three hundred thirty-three thousand, one hundred thirty-one".