1401012512553 has 4 divisors (see below), whose sum is σ = 1868016683408. Its totient is φ = 934008341700.

The previous prime is 1401012512539. The next prime is 1401012512573. The reversal of 1401012512553 is 3552152101041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1401012512553 - 2⁶ = 1401012512489 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1401012512553.

It is not an unprimeable number, because it can be changed into a prime (1401012512513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233502085423 + ... + 233502085428.

It is an arithmetic number, because the mean of its divisors is an integer number (467004170852).

Almost surely, 2^{1401012512553} is an apocalyptic number.

It is an amenable number.

1401012512553 is a deficient number, since it is larger than the sum of its proper divisors (467004170855).

1401012512553 is an equidigital number, since it uses as much as digits as its factorization.

1401012512553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 467004170854.

The product of its (nonzero) digits is 6000, while the sum is 30.

Adding to 1401012512553 its reverse (3552152101041), we get a palindrome (4953164613594).

The spelling of 1401012512553 in words is "one trillion, four hundred one billion, twelve million, five hundred twelve thousand, five hundred fifty-three".