Base | Representation |
---|---|
bin | 11111110110110111110100… |
… | …101000111111110010010111 |
3 | 200101002102000000020022100122 |
4 | 133312313310220333302113 |
5 | 121331031224013104201 |
6 | 1213553430253102155 |
7 | 41340426114354344 |
oct | 3766676450776227 |
9 | 611072000208318 |
10 | 140110232550551 |
11 | 40709463676a9a |
12 | 1386a37548795b |
13 | 6024452150783 |
14 | 268552b3277cb |
15 | 112e8c6c1ce1b |
hex | 7f6df4a3fc97 |
140110232550551 has 4 divisors (see below), whose sum is σ = 140110395240672. Its totient is φ = 140110069860432.
The previous prime is 140110232550529. The next prime is 140110232550653. The reversal of 140110232550551 is 155055232011041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140110232550551 - 210 = 140110232549527 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140110262550551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80046335 + ... + 81777968.
It is an arithmetic number, because the mean of its divisors is an integer number (35027598810168).
Almost surely, 2140110232550551 is an apocalyptic number.
140110232550551 is a deficient number, since it is larger than the sum of its proper divisors (162690121).
140110232550551 is an equidigital number, since it uses as much as digits as its factorization.
140110232550551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 162690120.
The product of its (nonzero) digits is 30000, while the sum is 35.
Adding to 140110232550551 its reverse (155055232011041), we get a palindrome (295165464561592).
The spelling of 140110232550551 in words is "one hundred forty trillion, one hundred ten billion, two hundred thirty-two million, five hundred fifty thousand, five hundred fifty-one".
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