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140111424111 = 346703808037
BaseRepresentation
bin1000001001111101001…
…0101010101001101111
3111101122121100210220010
42002133102222221233
54243422011032421
6144211042024303
713060043311641
oct2023722525157
9441577323803
10140111424111
115446a27878a
12231a3048093
131029b9a5619
146ad2354891
1539a08d1076
hex209f4aaa6f

140111424111 has 4 divisors (see below), whose sum is σ = 186815232152. Its totient is φ = 93407616072.

The previous prime is 140111424097. The next prime is 140111424113. The reversal of 140111424111 is 111424111041.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 140111424111 - 27 = 140111423983 is a prime.

It is a super-2 number, since 2×1401114241112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140111424113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23351904016 + ... + 23351904021.

It is an arithmetic number, because the mean of its divisors is an integer number (46703808038).

Almost surely, 2140111424111 is an apocalyptic number.

140111424111 is a deficient number, since it is larger than the sum of its proper divisors (46703808041).

140111424111 is an equidigital number, since it uses as much as digits as its factorization.

140111424111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46703808040.

The product of its (nonzero) digits is 128, while the sum is 21.

Adding to 140111424111 its reverse (111424111041), we get a palindrome (251535535152).

The spelling of 140111424111 in words is "one hundred forty billion, one hundred eleven million, four hundred twenty-four thousand, one hundred eleven".

Divisors: 1 3 46703808037 140111424111