Base | Representation |
---|---|
bin | 1000001001111101001… |
… | …0101010101001101111 |
3 | 111101122121100210220010 |
4 | 2002133102222221233 |
5 | 4243422011032421 |
6 | 144211042024303 |
7 | 13060043311641 |
oct | 2023722525157 |
9 | 441577323803 |
10 | 140111424111 |
11 | 5446a27878a |
12 | 231a3048093 |
13 | 1029b9a5619 |
14 | 6ad2354891 |
15 | 39a08d1076 |
hex | 209f4aaa6f |
140111424111 has 4 divisors (see below), whose sum is σ = 186815232152. Its totient is φ = 93407616072.
The previous prime is 140111424097. The next prime is 140111424113. The reversal of 140111424111 is 111424111041.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 140111424111 - 27 = 140111423983 is a prime.
It is a super-2 number, since 2×1401114241112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140111424113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23351904016 + ... + 23351904021.
It is an arithmetic number, because the mean of its divisors is an integer number (46703808038).
Almost surely, 2140111424111 is an apocalyptic number.
140111424111 is a deficient number, since it is larger than the sum of its proper divisors (46703808041).
140111424111 is an equidigital number, since it uses as much as digits as its factorization.
140111424111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46703808040.
The product of its (nonzero) digits is 128, while the sum is 21.
Adding to 140111424111 its reverse (111424111041), we get a palindrome (251535535152).
The spelling of 140111424111 in words is "one hundred forty billion, one hundred eleven million, four hundred twenty-four thousand, one hundred eleven".
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