Base | Representation |
---|---|
bin | 1100101111100011111100… |
… | …0110101100110001110001 |
3 | 1211121110110112210210001102 |
4 | 3023320333012230301301 |
5 | 3314030010430243213 |
6 | 45444401543014145 |
7 | 2644164432204461 |
oct | 313707706546161 |
9 | 54543415723042 |
10 | 14011242040433 |
11 | 451215294aaa0 |
12 | 16a358073a355 |
13 | 7a8340065091 |
14 | 36620d545ba1 |
15 | 1946e7d4d158 |
hex | cbe3f1acc71 |
14011242040433 has 32 divisors (see below), whose sum is σ = 15781414239360. Its totient is φ = 12327612687360.
The previous prime is 14011242040429. The next prime is 14011242040447. The reversal of 14011242040433 is 33404024211041.
It is not a de Polignac number, because 14011242040433 - 22 = 14011242040429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14011242040396 and 14011242040405.
It is not an unprimeable number, because it can be changed into a prime (14011242040423) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 66749438 + ... + 66959016.
It is an arithmetic number, because the mean of its divisors is an integer number (493169194980).
Almost surely, 214011242040433 is an apocalyptic number.
It is an amenable number.
14011242040433 is a deficient number, since it is larger than the sum of its proper divisors (1770172198927).
14011242040433 is a wasteful number, since it uses less digits than its factorization.
14011242040433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 210497.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 14011242040433 its reverse (33404024211041), we get a palindrome (47415266251474).
The spelling of 14011242040433 in words is "fourteen trillion, eleven billion, two hundred forty-two million, forty thousand, four hundred thirty-three".
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