1401130001211 has 4 divisors (see below), whose sum is σ = 1868173334952. Its totient is φ = 934086667472.

The previous prime is 1401130001191. The next prime is 1401130001221. The reversal of 1401130001211 is 1121000311041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1401130001211 - 2⁵ = 1401130001179 is a prime.

It is a super-2 number, since 2×1401130001211² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1401130001221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233521666866 + ... + 233521666871.

It is an arithmetic number, because the mean of its divisors is an integer number (467043333738).

Almost surely, 2^{1401130001211} is an apocalyptic number.

1401130001211 is a deficient number, since it is larger than the sum of its proper divisors (467043333741).

1401130001211 is an equidigital number, since it uses as much as digits as its factorization.

1401130001211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 467043333740.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 1401130001211 its reverse (1121000311041), we get a palindrome (2522130312252).

The spelling of 1401130001211 in words is "one trillion, four hundred one billion, one hundred thirty million, one thousand, two hundred eleven".