14011315151 has 4 divisors (see below), whose sum is σ = 14241008904. Its totient is φ = 13781621400.

The previous prime is 14011315127. The next prime is 14011315159. The reversal of 14011315151 is 15151311041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15151311041 = 37 ⋅409494893.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14011315151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14011315159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114846785 + ... + 114846906.

It is an arithmetic number, because the mean of its divisors is an integer number (3560252226).

Almost surely, 2^14011315151 is an apocalyptic number.

14011315151 is a deficient number, since it is larger than the sum of its proper divisors (229693753).

14011315151 is an equidigital number, since it uses as much as digits as its factorization.

14011315151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 229693752.

The product of its (nonzero) digits is 300, while the sum is 23.

Adding to 14011315151 its reverse (15151311041), we get a palindrome (29162626192).

The spelling of 14011315151 in words is "fourteen billion, eleven million, three hundred fifteen thousand, one hundred fifty-one".