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1401133503 = 37116065513
BaseRepresentation
bin101001110000011…
…1001100110111111
310121122110221211110
41103200321212333
510332142233003
6351011053103
746502303220
oct12340714677
93548427743
101401133503
116599a3380
123312a1193
131943876a3
14d4129247
158301aa03
hex538399bf

1401133503 has 16 divisors (see below), whose sum is σ = 2329157376. Its totient is φ = 727861440.

The previous prime is 1401133477. The next prime is 1401133519. The reversal of 1401133503 is 3053311041.

It is not a de Polignac number, because 1401133503 - 25 = 1401133471 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a self number, because there is not a number n which added to its sum of digits gives 1401133503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1401133103) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3032526 + ... + 3032987.

It is an arithmetic number, because the mean of its divisors is an integer number (145572336).

Almost surely, 21401133503 is an apocalyptic number.

1401133503 is a deficient number, since it is larger than the sum of its proper divisors (928023873).

1401133503 is a wasteful number, since it uses less digits than its factorization.

1401133503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6065534.

The product of its (nonzero) digits is 540, while the sum is 21.

The square root of 1401133503 is about 37431.7178740169. The cubic root of 1401133503 is about 1118.9907742732.

Adding to 1401133503 its reverse (3053311041), we get a palindrome (4454444544).

The spelling of 1401133503 in words is "one billion, four hundred one million, one hundred thirty-three thousand, five hundred three".

Divisors: 1 3 7 11 21 33 77 231 6065513 18196539 42458591 66720643 127375773 200161929 467044501 1401133503