140113410101111 has 4 divisors (see below), whose sum is σ = 142032771883392. Its totient is φ = 138194048318832.

The previous prime is 140113410101059. The next prime is 140113410101209. The reversal of 140113410101111 is 111101014311041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140113410101111 - 2³⁰ = 140112336359287 is a prime.

It is a super-2 number, since 2×140113410101111² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140113410101311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 959680891031 + ... + 959680891176.

It is an arithmetic number, because the mean of its divisors is an integer number (35508192970848).

Almost surely, 2^{140113410101111} is an apocalyptic number.

140113410101111 is a deficient number, since it is larger than the sum of its proper divisors (1919361782281).

140113410101111 is an equidigital number, since it uses as much as digits as its factorization.

140113410101111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1919361782280.

The product of its (nonzero) digits is 48, while the sum is 20.

Adding to 140113410101111 its reverse (111101014311041), we get a palindrome (251214424412152).

The spelling of 140113410101111 in words is "one hundred forty trillion, one hundred thirteen billion, four hundred ten million, one hundred one thousand, one hundred eleven".