Search a number
-
+
1401150121 = 73126324551
BaseRepresentation
bin101001110000011…
…1101101010101001
310121122111210121221
41103200331222221
510332143300441
6351011302041
746502402530
oct12340755251
93548453557
101401150121
11659a04908
123312aa921
13194392117
14d4131317
15830208d1
hex5383daa9

1401150121 has 16 divisors (see below), whose sum is σ = 1659322368. Its totient is φ = 1157778000.

The previous prime is 1401150103. The next prime is 1401150131. The reversal of 1401150121 is 1210511041.

It is a cyclic number.

It is not a de Polignac number, because 1401150121 - 215 = 1401117353 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1401150095 and 1401150104.

It is not an unprimeable number, because it can be changed into a prime (1401150131) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 44796 + ... + 69346.

It is an arithmetic number, because the mean of its divisors is an integer number (103707648).

Almost surely, 21401150121 is an apocalyptic number.

It is an amenable number.

1401150121 is a deficient number, since it is larger than the sum of its proper divisors (258172247).

1401150121 is a wasteful number, since it uses less digits than its factorization.

1401150121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24852.

The product of its (nonzero) digits is 40, while the sum is 16.

The square root of 1401150121 is about 37431.9398508814. The cubic root of 1401150121 is about 1118.9951981475.

Adding to 1401150121 its reverse (1210511041), we get a palindrome (2611661162).

The spelling of 1401150121 in words is "one billion, four hundred one million, one hundred fifty thousand, one hundred twenty-one".

Divisors: 1 7 31 217 263 1841 8153 24551 57071 171857 761081 5327567 6456913 45198391 200164303 1401150121