1401150103 has 2 divisors, whose sum is σ = 1401150104. Its totient is φ = 1401150102.

The previous prime is 1401150071. The next prime is 1401150131. The reversal of 1401150103 is 3010511041.

It is a strong prime.

It is an emirp because it is prime and its reverse (3010511041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1401150103 - 2⁵ = 1401150071 is a prime.

It is a super-2 number, since 2×1401150103² = 3926443222273821218, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1401157103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700575051 + 700575052.

It is an arithmetic number, because the mean of its divisors is an integer number (700575052).

Almost surely, 2^1401150103 is an apocalyptic number.

1401150103 is a deficient number, since it is larger than the sum of its proper divisors (1).

1401150103 is an equidigital number, since it uses as much as digits as its factorization.

1401150103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 16.

The square root of 1401150103 is about 37431.9396104450. The cubic root of 1401150103 is about 1118.9951933557.

Adding to 1401150103 its reverse (3010511041), we get a palindrome (4411661144).

The spelling of 1401150103 in words is "one billion, four hundred one million, one hundred fifty thousand, one hundred three".