Base | Representation |
---|---|
bin | 10100011000111110000… |
… | …011011010011000110011 |
3 | 11221221202001210110200210 |
4 | 110120332003122120303 |
5 | 140424124301423103 |
6 | 2551411431515203 |
7 | 203143024026000 |
oct | 24307603323063 |
9 | 4857661713623 |
10 | 1401200420403 |
11 | 4a0278120973 |
12 | 1a768b228b03 |
13 | a21955177c4 |
14 | 4bb65c088a7 |
15 | 266ad72ee03 |
hex | 1463e0da633 |
1401200420403 has 32 divisors (see below), whose sum is σ = 2179130688000. Its totient is φ = 800541382368.
The previous prime is 1401200420401. The next prime is 1401200420443. The reversal of 1401200420403 is 3040240021041.
It is not a de Polignac number, because 1401200420403 - 21 = 1401200420401 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 1401200420403.
It is not an unprimeable number, because it can be changed into a prime (1401200420401) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5713300 + ... + 5953502.
It is an arithmetic number, because the mean of its divisors is an integer number (68097834000).
Almost surely, 21401200420403 is an apocalyptic number.
1401200420403 is a deficient number, since it is larger than the sum of its proper divisors (777930267597).
1401200420403 is an equidigital number, since it uses as much as digits as its factorization.
1401200420403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 245896 (or 245882 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 21.
Adding to 1401200420403 its reverse (3040240021041), we get a palindrome (4441440441444).
The spelling of 1401200420403 in words is "one trillion, four hundred one billion, two hundred million, four hundred twenty thousand, four hundred three".
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