14012033101441 has 4 divisors (see below), whose sum is σ = 14028459870292. Its totient is φ = 13995606332592.

The previous prime is 14012033101411. The next prime is 14012033101483. The reversal of 14012033101441 is 14410133021041.

14012033101441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6417026244225 + 7595006857216 = 2533185^2 + 2755904^2 .

It is a cyclic number.

It is not a de Polignac number, because 14012033101441 - 2²⁵ = 14011999547009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14012033101411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8213383146 + ... + 8213384851.

It is an arithmetic number, because the mean of its divisors is an integer number (3507114967573).

Almost surely, 2^{14012033101441} is an apocalyptic number.

It is an amenable number.

14012033101441 is a deficient number, since it is larger than the sum of its proper divisors (16426768851).

14012033101441 is an equidigital number, since it uses as much as digits as its factorization.

14012033101441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16426768850.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14012033101441 its reverse (14410133021041), we get a palindrome (28422166122482).

The spelling of 14012033101441 in words is "fourteen trillion, twelve billion, thirty-three million, one hundred one thousand, four hundred forty-one".