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14012033330401 = 65101215235301
BaseRepresentation
bin1100101111100110111001…
…0001001110110011100001
31211121112111200202110211021
43023321232101032303201
53314033121013033101
645445012251045441
72644223151103351
oct313715621166341
954545450673737
1014012033330401
114512519581947
1216a3761740881
137a8437c885b2
14366286684b61
151947425545a1
hexcbe6e44ece1

14012033330401 has 4 divisors (see below), whose sum is σ = 14012248630804. Its totient is φ = 14011818030000.

The previous prime is 14012033330297. The next prime is 14012033330411. The reversal of 14012033330401 is 10403333021041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6684189744400 + 7327843586001 = 2585380^2 + 2706999^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14012033330401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14012033330411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107552550 + ... + 107682751.

It is an arithmetic number, because the mean of its divisors is an integer number (3503062157701).

Almost surely, 214012033330401 is an apocalyptic number.

It is an amenable number.

14012033330401 is a deficient number, since it is larger than the sum of its proper divisors (215300403).

14012033330401 is an equidigital number, since it uses as much as digits as its factorization.

14012033330401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 215300402.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 14012033330401 its reverse (10403333021041), we get a palindrome (24415366351442).

The spelling of 14012033330401 in words is "fourteen trillion, twelve billion, thirty-three million, three hundred thirty thousand, four hundred one".

Divisors: 1 65101 215235301 14012033330401