140120443044301 has 4 divisors (see below), whose sum is σ = 140120611388604. Its totient is φ = 140120274700000.

The previous prime is 140120443044269. The next prime is 140120443044341. The reversal of 140120443044301 is 103440344021041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 78007933484100 + 62112509560201 = 8832210^2 + 7881149^2 .

It is a cyclic number.

It is not a de Polignac number, because 140120443044301 - 2⁵ = 140120443044269 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140120443044341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82917400 + ... + 84590401.

It is an arithmetic number, because the mean of its divisors is an integer number (35030152847151).

Almost surely, 2^{140120443044301} is an apocalyptic number.

It is an amenable number.

140120443044301 is a deficient number, since it is larger than the sum of its proper divisors (168344303).

140120443044301 is an equidigital number, since it uses as much as digits as its factorization.

140120443044301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 168344302.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 140120443044301 its reverse (103440344021041), we get a palindrome (243560787065342).

The spelling of 140120443044301 in words is "one hundred forty trillion, one hundred twenty billion, four hundred forty-three million, forty-four thousand, three hundred one".