Base | Representation |
---|---|
bin | 10100011000111110110… |
… | …011011111100000110111 |
3 | 11221221202221111211000012 |
4 | 110120332303133200313 |
5 | 140424141013234221 |
6 | 2551413002010435 |
7 | 203143236122042 |
oct | 24307663374067 |
9 | 4857687454005 |
10 | 1401213024311 |
11 | 4a028424a421 |
12 | 1a76934a6a1b |
13 | a219800b639 |
14 | 4bb67769c59 |
15 | 266ae8be65b |
hex | 1463ecdf837 |
1401213024311 has 4 divisors (see below), whose sum is σ = 1401632176032. Its totient is φ = 1400793872592.
The previous prime is 1401213024283. The next prime is 1401213024313. The reversal of 1401213024311 is 1134203121041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1401213024311 - 218 = 1401212762167 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1401213024313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 209570846 + ... + 209577531.
It is an arithmetic number, because the mean of its divisors is an integer number (350408044008).
Almost surely, 21401213024311 is an apocalyptic number.
1401213024311 is a deficient number, since it is larger than the sum of its proper divisors (419151721).
1401213024311 is an equidigital number, since it uses as much as digits as its factorization.
1401213024311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 419151720.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1401213024311 its reverse (1134203121041), we get a palindrome (2535416145352).
The spelling of 1401213024311 in words is "one trillion, four hundred one billion, two hundred thirteen million, twenty-four thousand, three hundred eleven".
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