14012232420033 has 12 divisors (see below), whose sum is σ = 20937818559060. Its totient is φ = 9019367994336.

The previous prime is 14012232420001. The next prime is 14012232420041. The reversal of 14012232420033 is 33002423221041.

14012232420033 is a `hidden beast` number, since 1 + 4 + 0 + 1 + 2 + 232 + 420 + 0 + 3 + 3 = 666.

14012232420033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 6300014660289 + 7712217759744 = 2509983^2 + 2777088^2 .

It is not a de Polignac number, because 14012232420033 - 2⁵ = 14012232420001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14012232419979 and 14012232420006.

It is not an unprimeable number, because it can be changed into a prime (14012232420533) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 26843356866 + ... + 26843357387.

It is an arithmetic number, because the mean of its divisors is an integer number (1744818213255).

Almost surely, 2^{14012232420033} is an apocalyptic number.

It is an amenable number.

14012232420033 is a deficient number, since it is larger than the sum of its proper divisors (6925586139027).

14012232420033 is a wasteful number, since it uses less digits than its factorization.

14012232420033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 53686714288 (or 53686714285 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 14012232420033 its reverse (33002423221041), we get a palindrome (47014655641074).

The spelling of 14012232420033 in words is "fourteen trillion, twelve billion, two hundred thirty-two million, four hundred twenty thousand, thirty-three".