Base | Representation |
---|---|
bin | 1100101111100111111011… |
… | …0101010000100110100011 |
3 | 1211121120020001122020112012 |
4 | 3023321332311100212203 |
5 | 3314034203132213103 |
6 | 45445100015023135 |
7 | 2644233064044212 |
oct | 313717665204643 |
9 | 54546201566465 |
10 | 14012311210403 |
11 | 4512651418240 |
12 | 16a381a80aaab |
13 | 7a848071002c |
14 | 3662b153b079 |
15 | 19475bb442d8 |
hex | cbe7ed509a3 |
14012311210403 has 16 divisors (see below), whose sum is σ = 15403235823360. Its totient is φ = 12640904546400.
The previous prime is 14012311210397. The next prime is 14012311210409. The reversal of 14012311210403 is 30401211321041.
It is an interprime number because it is at equal distance from previous prime (14012311210397) and next prime (14012311210409).
It is a cyclic number.
It is not a de Polignac number, because 14012311210403 - 224 = 14012294433187 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14012311210409) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 71128826 + ... + 71325552.
It is an arithmetic number, because the mean of its divisors is an integer number (962702238960).
Almost surely, 214012311210403 is an apocalyptic number.
14012311210403 is a deficient number, since it is larger than the sum of its proper divisors (1390924612957).
14012311210403 is a wasteful number, since it uses less digits than its factorization.
14012311210403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 246298.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 14012311210403 its reverse (30401211321041), we get a palindrome (44413522531444).
The spelling of 14012311210403 in words is "fourteen trillion, twelve billion, three hundred eleven million, two hundred ten thousand, four hundred three".
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