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14012311211323 = 50927529098647
BaseRepresentation
bin1100101111100111111011…
…0101010000110100111011
31211121120020001122021210021
43023321332311100310323
53314034203132230243
645445100015031311
72644233064046665
oct313717665206473
954546201567707
1014012311211323
1145126514189a7
1216a381a80b537
137a8480710589
143662b153b535
1519475bb446ed
hexcbe7ed50d3b

14012311211323 has 4 divisors (see below), whose sum is σ = 14039840310480. Its totient is φ = 13984782112168.

The previous prime is 14012311211309. The next prime is 14012311211411. The reversal of 14012311211323 is 32311211321041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14012311211323 - 213 = 14012311203131 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14012311211023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13764548815 + ... + 13764549832.

It is an arithmetic number, because the mean of its divisors is an integer number (3509960077620).

Almost surely, 214012311211323 is an apocalyptic number.

14012311211323 is a deficient number, since it is larger than the sum of its proper divisors (27529099157).

14012311211323 is an equidigital number, since it uses as much as digits as its factorization.

14012311211323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27529099156.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 14012311211323 its reverse (32311211321041), we get a palindrome (46323522532364).

The spelling of 14012311211323 in words is "fourteen trillion, twelve billion, three hundred eleven million, two hundred eleven thousand, three hundred twenty-three".

Divisors: 1 509 27529098647 14012311211323