Base | Representation |
---|---|
bin | 1100101111100111111110… |
… | …0010010100010010110010 |
3 | 1211121120020212212022222211 |
4 | 3023321333202110102302 |
5 | 3314034214143201002 |
6 | 45445101120122334 |
7 | 2644233266330314 |
oct | 313717742242262 |
9 | 54546225768884 |
10 | 14012323022002 |
11 | 4512658055498 |
12 | 16a38227663aa |
13 | 7a8482cb7346 |
14 | 3662b2d337b4 |
15 | 19475cbc8dd7 |
hex | cbe7f8944b2 |
14012323022002 has 4 divisors (see below), whose sum is σ = 21018484533006. Its totient is φ = 7006161511000.
The previous prime is 14012323021967. The next prime is 14012323022053. The reversal of 14012323022002 is 20022032321041.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13947603153201 + 64719868801 = 3734649^2 + 254401^2 .
It is a super-3 number, since 3×140123230220023 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3503080755499 + ... + 3503080755502.
Almost surely, 214012323022002 is an apocalyptic number.
14012323022002 is a deficient number, since it is larger than the sum of its proper divisors (7006161511004).
14012323022002 is an equidigital number, since it uses as much as digits as its factorization.
14012323022002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7006161511003.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 14012323022002 its reverse (20022032321041), we get a palindrome (34034355343043).
The spelling of 14012323022002 in words is "fourteen trillion, twelve billion, three hundred twenty-three million, twenty-two thousand, two".
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