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14012323022002 = 27006161511001
BaseRepresentation
bin1100101111100111111110…
…0010010100010010110010
31211121120020212212022222211
43023321333202110102302
53314034214143201002
645445101120122334
72644233266330314
oct313717742242262
954546225768884
1014012323022002
114512658055498
1216a38227663aa
137a8482cb7346
143662b2d337b4
1519475cbc8dd7
hexcbe7f8944b2

14012323022002 has 4 divisors (see below), whose sum is σ = 21018484533006. Its totient is φ = 7006161511000.

The previous prime is 14012323021967. The next prime is 14012323022053. The reversal of 14012323022002 is 20022032321041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13947603153201 + 64719868801 = 3734649^2 + 254401^2 .

It is a super-3 number, since 3×140123230220023 (a number of 40 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3503080755499 + ... + 3503080755502.

Almost surely, 214012323022002 is an apocalyptic number.

14012323022002 is a deficient number, since it is larger than the sum of its proper divisors (7006161511004).

14012323022002 is an equidigital number, since it uses as much as digits as its factorization.

14012323022002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7006161511003.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 14012323022002 its reverse (20022032321041), we get a palindrome (34034355343043).

The spelling of 14012323022002 in words is "fourteen trillion, twelve billion, three hundred twenty-three million, twenty-two thousand, two".

Divisors: 1 2 7006161511001 14012323022002